Statics 12th Edition Solutions |link| - Vector Mechanics For Engineers

R = √(Rx^2 + Ry^2) = √(161.60^2 + 179.90^2) = 243.30 N θ = tan^(-1)(Ry/Rx) = tan^(-1)(179.90/161.60) = 48.19°

MO = (3(0) - 4(0))i - (2(0) - 4(200))j + (2(0) - 3(200))k = 0i + 800j - 600k

Calculate the x- and y-components of each force. R = √(Rx^2 + Ry^2) = √(161

MO = √(800^2 + (-600)^2) = 1000 N·m

MO = rOA × F = |i j k| |2 3 4| |Fx Fy Fz| R = √(Rx^2 + Ry^2) = √(161

Rx = F1x + F2x = 86.60 + 75 = 161.60 N Ry = F1y + F2y = 50 + 129.90 = 179.90 N

A classic textbook!

Let's take a look at some key problems and their solutions in the 12th edition: